kemi, bindningar & krafter Flashcards | Quizlet
Given ({:(56),(26):}Fe)= 55. 934939u and m ({:(209),(83):}Bi)= 208. 980388u8 m ("proton") =1.007825u, m ("nutron")=1.008665u Then, BE per nucleon of Fe and Bi are respectively
bindningsenergi per nukleon (Fysik/Fysik 1) – Pluggakuten
Varför är järn toppen av den bindande energikurvan?
The binding energy of an imaginary iron ^5636Fe is (Given atomic mass of Fe is 55.9349 amu and that of hydrogen is 1.00783 amu. Mass of neutron is 1.00876 amu)
Bindningsenergi och massa per nukleon
Given ({:(56),(26):}Fe)= 55. 934939u and m ({:(209),(83):}Bi)= 208. 980388u8 m ("proton") =1.007825u, m ("nutron")=1.008665u Then, BE per nucleon of Fe and Bi are respectively
LEKTION 26
kemi, bindningar & krafter Flashcards | Quizlet
Find BE per nucleon of ^56Fe where m(^56Fe) = 55.936u mn = 1.00727u, mp = 1.007274 u .
